>> run_me1_3
*************** Specifications on Given Computing Machine ***********************
Floating point relative accuracy (eps) is: 2.220446e-016 
Smallest positive floating point number is: 2.225074e-308 
Largest positive floating point number is: 1.797693e+308 
*********************************************************************************

 Function Name: f

************************** Initial Input Values: ********************************
x_0= 1.000000e+000, x_1=-1.000000e+000, f(x_0)= 5.000000e+000, f(x_1)= 1.000000e+000 
*********************************************************************************

n= 0 a= -1.000000e+000, f(a)= 1.000000e+000 
n= 1 a= 1.000000e+000, f(a)= 5.000000e+000 
n= 2, a= -1.500000e+000, f(a)= -7.968750e+000 
n= 3, a= -1.055749e+000, f(a)= 5.116487e-001 
n= 4, a= -1.114158e+000, f(a)= -9.991207e-002 
n= 5, a= -1.104615e+000, f(a)= 7.593217e-003 
n= 6, a= -1.105289e+000, f(a)= 1.011787e-004 
n= 7, a= -1.105299e+000, f(a)= -1.045169e-007 
n= 8, a= -1.105299e+000, f(a)= 1.436185e-012 
n= 9, a= -1.105299e+000, f(a)= 0.000000e+000 

**************** Result Has Converged: *********************
Converged within the tolerance 2.220446e-016 
The found zero is: -1.105299e+000 
************************************************************

the requested number of movie frames 10 is too large and 
 will be reduced to 8 to match the data 
>>